The displacement-time graph of a particle moving with uniform velocity is a straight line. The slope of this line gives the velocity of the particle.

In this case, the slopes of the lines for particles A and B are given by the tangent of the angles they make with the time axis.

For particle A, the slope (and hence velocity vA) is tan(30º) = √3/3.
For particle B, the slope (and hence velocity vB) is tan(60º) = √3.

The ratio of the velocities vA : vB is therefore (√3/3) : √3 = 1 : 3.

So, the ratio of velocities of vA : vB is 1 : 3.

Question

The displacement-time graph of a particle moving with uniform velocity is a straight line. The slope of this line gives the velocity of the particle.

In this case, the slopes of the lines for particles A and B are given by the tangent of the angles they make with the time axis.

For particle A, the slope (and hence velocity vA) is tan(30º) = √3/3.
For particle B, the slope (and hence velocity vB) is tan(60º) = √3.

The ratio of the velocities vA : vB is therefore (√3/3) : √3 = 1 : 3.

So, the ratio of velocities of vA : vB is 1 : 3.

Knowee AI · Accepted Answer

The displacement-time graph of a particle moving with uniform velocity is a straight line. The slope of this line gives the velocity of the particle.

In this case, the slopes of the lines for particles A and B are given by the tangent of the angles they make with the time axis.

For particle A, the slope (and hence velocity vA) is tan(30º) = √3/3.
For particle B, the slope (and hence velocity vB) is tan(60º) = √3.

The ratio of the velocities vA : vB is therefore (√3/3) : √3 = 1 : 3.

So, the ratio of velocities of vA : vB is 1 : 3.

The displacement-time graph of two particle A & B are straight lines inclined at angles of 30º & 60º with the time axis. The ratio of velocities of vA : vB is :-1 : 21 : 3