The sum of the first 30 terms of an arithmetic progression is 40. The sum of its first 60 terms is also 40. Find the sum of its 31st and 60th termsa.600b.40c.1200d.0
Question
The sum of the first 30 terms of an arithmetic progression is 40. The sum of its first 60 terms is also 40. Find the sum of its 31st and 60th termsa.600b.40c.1200d.0
Solution
The sum of the first 30 terms of an arithmetic progression is given by the formula:
S_30 = 30/2 * (2a + (30-1)d) = 40
The sum of the first 60 terms of an arithmetic progression is given by the formula:
S_60 = 60/2 * (2a + (60-1)d) = 40
From these two equations, we can see that the sum of the first 30 terms is equal to the sum of the first 60 terms. This means that the sum of the terms from the 31st to the 60th term is 0.
Therefore, the sum of the 31st and 60th terms is also 0.
So, the answer is d.0.
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