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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an left bracket, x, comma, y, right bracket(x,y) point.y, equals, x, squared, minus, 12, x, plus, 29y=x 2 −12x+29

Question

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an left bracket, x, comma, y, right bracket(x,y) point.y, equals, x, squared, minus, 12, x, plus, 29y=x 2 −12x+29

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Solution

The vertex of a parabola given by the equation y = ax^2 + bx + c is given by the point (h, k), where h = -b/2a and k is the value of y at x = h.

Given the equation y = x^2 - 12x + 29, we can see that a = 1 and b = -12.

So, h = -b/2a = -(-12)/(2*1) = 6.

To find k, we substitute h = 6 into the equation:

k = (6)^2 - 12*(6) + 29 = 36 - 72 + 29 = -7.

So, the vertex of the parabola is (6, -7).

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