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Mr. Price deposited $170 in his bank. The number of $5 bills was 3 times the number of$10 bills, and the number of $1 bills was 30 more than the number of $5 bills. How manybills of each type did he deposit?

Question

Mr. Price deposited 170inhisbank.Thenumberof170 in his bank. The number of 5 bills was 3 times the number of10bills,andthenumberof10 bills, and the number of 1 bills was 30 more than the number of $5 bills. How manybills of each type did he deposit?

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Solution

Let's denote the number of 10billsasx,thenumberof10 bills as x, the number of 5 bills as 3x (since it's three times the number of 10bills),andthenumberof10 bills), and the number of 1 bills as 3x + 30 (since it's 30 more than the number of $5 bills).

According to the problem, the total amount of money is $170. We can express this as an equation:

10x (total amount of 10bills)+53x(totalamountof10 bills) + 5*3x (total amount of 5 bills) + 1*(3x + 30) (total amount of $1 bills) = 170

Solving this equation will give us the number of each type of bill.

Let's simplify the equation:

10x + 15x + 3x + 30 = 170

Combine like terms:

28x + 30 = 170

Subtract 30 from both sides:

28x = 140

Divide both sides by 28:

x = 5

So, Mr. Price deposited 5 $10 bills.

The number of 5billsis3timesthenumberof5 bills is 3 times the number of 10 bills, so he deposited 3*5 = 15 $5 bills.

The number of 1billsis30morethanthenumberof1 bills is 30 more than the number of 5 bills, so he deposited 15 + 30 = 45 $1 bills.

This problem has been solved

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