Pure water boils at 100 ∘ C, has a specific latent heat of vaporisation of 2260kJ/kg and a specific heat capacity of 4200J/(kg ∘ C).Part AEnergy to boil waterAll questions in this part are answered incorrectlyHow much energy is required for 2.0kg of water to boil away if it is already at 100 ∘ C?
Question
Pure water boils at 100 ∘ C, has a specific latent heat of vaporisation of 2260kJ/kg and a specific heat capacity of 4200J/(kg ∘ C).Part AEnergy to boil waterAll questions in this part are answered incorrectlyHow much energy is required for 2.0kg of water to boil away if it is already at 100 ∘ C?
Solution
The energy required to boil away 2.0 kg of water that is already at 100 °C can be calculated using the formula:
Q = mL
where:
- Q is the heat energy,
- m is the mass of the substance, and
- L is the specific latent heat of vaporisation.
Given that:
- m = 2.0 kg, and
- L = 2260 kJ/kg = 2260000 J/kg (we convert kJ to J because the unit of specific heat capacity is in J),
we can substitute these values into the formula to get:
Q = 2.0 kg * 2260000 J/kg = 4520000 J
So, the energy required to boil away 2.0 kg of water that is already at 100 °C is 4520000 J.
Similar Questions
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