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Find the remainder when (9)^87 is divided by 6 ?4531

Question

Find the remainder when (9)^87 is divided by 6 ?4531

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Solution

To find the remainder when (9)^87 is divided by 6, we first need to find the pattern of remainders when powers of 9 are divided by 6.

  1. 9^1 = 9, remainder when divided by 6 is 3.
  2. 9^2 = 81, remainder when divided by 6 is 3.
  3. 9^3 = 729, remainder when divided by 6 is 3.
  4. 9^4 = 6561, remainder when divided by 6 is 3.

As you can see, the remainder is always 3 when a power of 9 is divided by 6. Therefore, the remainder when (9)^87 is divided by 6 is also 3.

This problem has been solved

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