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How many moles of air are there in a 3 L container at 1 atm pressure and 293 K? Use PV = nRT.A.0.125 molesB.8.02 molesC.0.042 molesD.36.54 molesSUBMITarrow_backPREVIOUS

Question

How many moles of air are there in a 3 L container at 1 atm pressure and 293 K? Use PV = nRT.A.0.125 molesB.8.02 molesC.0.042 molesD.36.54 molesSUBMITarrow_backPREVIOUS

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Solution

To solve this problem, we will use the ideal gas law equation: PV = nRT

Where: P = pressure = 1 atm V = volume = 3 L n = number of moles (what we're solving for) R = ideal gas constant = 0.0821 L.atm/(mol.K) (this is the value of R when pressure is in atm and volume is in liters) T = temperature = 293 K

Rearranging the equation to solve for n, we get: n = PV/RT

Substituting the given values into the equation, we get: n = (1 atm * 3 L) / (0.0821 L.atm/(mol.K) * 293 K)

Solving this gives: n ≈ 0.125 moles

So, the answer is A. 0.125 moles.

This problem has been solved

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