One year ago, a father was 8 times as old as his son. Now, his age is the square of his son’s age. Find the age of the father24494825
Question
One year ago, a father was 8 times as old as his son. Now, his age is the square of his son’s age. Find the age of the father24494825
Solution 1
Let's denote the current age of the son as x and the current age of the father as y.
From the problem, we have two equations:
-
One year ago, the father was 8 times as old as his son. This can be written as: y - 1 = 8 * (x - 1)
-
Now, the father's age is the square of his son's age. This can be written as: y = x^2
Now, we can solve these equations step by step:
Step 1: Substitute the second equation into the first one: x^2 - 1 = 8 * (x - 1)
Step 2: Simplify the equation: x^2 - 1 = 8x - 8
Step 3: Rearrange the equation: x^2 - 8x + 7 = 0
Step 4: Factor the equation: (x - 7)(x - 1) = 0
Step 5: Solve for x: x = 7 or x = 1
Since the son's age cannot be 1 (because one year ago he would have been 0 and the father's age would not have been 8 times his), the son must be 7 years old.
Step 6: Substitute x = 7 into the second equation to find y: y = (7)^2 = 49
So, the father is 49 years old.
Solution 2
Let's denote the current age of the son as x and the current age of the father as y.
From the problem, we have two equations:
-
One year ago, the father was 8 times as old as his son. This can be written as: y - 1 = 8 * (x - 1)
-
Now, the father's age is the square of his son's age. This can be written as: y = x^2
Now we can solve these equations step by step:
Step 1: Substitute the second equation into the first one: x^2 - 1 = 8 * (x - 1)
Step 2: Simplify the equation: x^2 - 1 = 8x - 8
Step 3: Rearrange the equation: x^2 - 8x + 7 = 0
Step 4: Factor the equation: (x - 7)(x - 1) = 0
Step 5: Solve for x: x = 7 or x = 1
Since the son's age cannot be 1 (because one year ago he would have been 0 and the father's age cannot be 8 times 0), the son must be 7 years old.
Step 6: Substitute x = 7 into the second equation: y = 7^2 = 49
So, the father is 49 years old.
Solution 3
Let's denote the current age of the son as x and the current age of the father as y.
From the problem, we have two equations:
-
One year ago, the father was 8 times as old as his son. This can be written as: y - 1 = 8 * (x - 1)
-
Now, the father's age is the square of his son's age. This can be written as: y = x^2
Now, we can solve these equations step by step:
Step 1: Substitute the second equation into the first one: x^2 - 1 = 8 * (x - 1)
Step 2: Simplify the equation: x^2 - 1 = 8x - 8
Step 3: Rearrange the equation: x^2 - 8x + 7 = 0
Step 4: Factor the equation: (x - 7)(x - 1) = 0
Step 5: Solve for x: x = 7 or x = 1
Since the son's age cannot be 1 (because one year ago he would have been 0 and the father would not have been 8 times his age), the son must be 7 years old.
Step 6: Substitute x = 7 into the second equation to find y: y = (7)^2 = 49
So, the father is 49 years old.
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