Calculate the mass (in g) of potassium permanganate (KMnO4) required to make a 250 mL of a 0.951 M solution. Answer to 3 decimal places.MW(KMnO4) = 158.04 g.mol-1
Question
Calculate the mass (in g) of potassium permanganate (KMnO4) required to make a 250 mL of a 0.951 M solution. Answer to 3 decimal places.MW(KMnO4) = 158.04 g.mol-1
Solution
Step 1: Identify the given values
The molarity (M) of KMnO4 = 0.951 M The volume (V) of the solution = 250 mL = 0.250 L (since 1L = 1000mL) The molar mass (MW) of KMnO4 = 158.04 g/mol
Step 2: Calculate the number of moles (n) of KMnO4
The formula to calculate the number of moles from molarity and volume is:
n = M * V
Substitute the given values into the formula:
n = 0.951 mol/L * 0.250 L = 0.23775 mol
Step 3: Calculate the mass (m) of KMnO4
The formula to calculate the mass from the number of moles and molar mass is:
m = n * MW
Substitute the given values into the formula:
m = 0.23775 mol * 158.04 g/mol = 37.586 g
So, 37.586 g of potassium permanganate is required to make a 250 mL of a 0.951 M solution.
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