7 participants participated in the competition,and there 3 of them will won a price and be ranked as 1st, 2nd and 3rd. How many possible combinations are there for the top 3 spots
Question
7 participants participated in the competition,and there 3 of them will won a price and be ranked as 1st, 2nd and 3rd. How many possible combinations are there for the top 3 spots
Solution
This is a permutation problem because the order in which the participants are ranked matters.
The formula for permutations is:
P(n, r) = n! / (n-r)!
where:
- n is the total number of options,
- r is the number of options chosen at a time,
- "!" denotes a factorial, which means multiplying all positive integers up to that number.
In this case, n = 7 (the total number of participants) and r = 3 (the number of spots to fill).
So, the calculation would be:
P(7, 3) = 7! / (7-3)!
= 7654321 / 432*1
= 765
= 210
So, there are 210 possible combinations for the top 3 spots.
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