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7 participants participated in the competition,and there 3 of them will won a price and be ranked as 1st, 2nd and 3rd. How many possible combinations are there for the top 3 spots

Question

7 participants participated in the competition,and there 3 of them will won a price and be ranked as 1st, 2nd and 3rd. How many possible combinations are there for the top 3 spots

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Solution

This is a permutation problem because the order in which the participants are ranked matters.

The formula for permutations is:

P(n, r) = n! / (n-r)!

where:

  • n is the total number of options,
  • r is the number of options chosen at a time,
  • "!" denotes a factorial, which means multiplying all positive integers up to that number.

In this case, n = 7 (the total number of participants) and r = 3 (the number of spots to fill).

So, the calculation would be:

P(7, 3) = 7! / (7-3)!

= 7654321 / 432*1

= 765

= 210

So, there are 210 possible combinations for the top 3 spots.

This problem has been solved

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