Suppose that the probability of event A is 0.2 and the probability of event B is 0.4. Also, suppose that the two events are independent. Then P(A|B) is:Question 16Select one:a.P(A)/P(B) = 0.2/0.4 = ½b.None of the above.c.P(A) = 0.2d.P(A) × P(B) = (0.2)(0.4) = 0.08

Given P(A) = 0.6 and P(B) = 0.4, do the following.(a) If A and B are independent events, compute P(A and B). (b) If P(A | B) = 0.1, compute P(A and B).

If the probability of Event A occurring is 0.6, and the probability of Event B occurring is 0.4, what is the probability of both events happening together, assuming they are independent?a.0.24b.0.1c.0.06d.0.16

A and B are independent events.P(A) = 0.40P(B) = 0.30What is P(A|B)?A.Not enough informationB.0.12C.0.40D.0.30

Let A and B be two events, P(A) = 0.4, P(B) = 0.6, P(A∩B) = 0.2，Find:P(A|B)(Please keep four decimal places

Given P(A) = 0.9 and P(B) = 0.3, do the following.(a) If A and B are independent events, compute P(A and B).(b) If P(A | B) = 0.6, compute P(A and B).Step 1(a) If A and B are independent events, compute P(A and B).To compute P(A and B) means that we wish to find the probability that both A happened and B happened.Recall that two events are independent if the occurrence or nonoccurrence of one event does not change the probability that the other event will occur.We are given that A and B are independent events, so we can use the multiplication rule for independent events. It is also given that P(A) = 0.9 and P(B) = 0.3.P(A and B)  =  P(A) · P(B) =  (0.9) ·    =