A company prints contest codes on its fun-size bags of candy. Each 6-character code consists of the letter A followed by the letter H followed by 4 of the digits 0 through 9. The digits may repeat. Which of the following expressions gives the number of different 6-character codes that are possible?F. 1(1)(10)(10)(10)(10) G. 2(1)(10)(9)(8)(7) H. 2(1)(10)(10)(10)(10) J. 2(2)(10)(9)(8)(7) K. 2(2)(10)(10)(10)(10) InfoInstr123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960 Flag
Question
A company prints contest codes on its fun-size bags of candy. Each 6-character code consists of the letter A followed by the letter H followed by 4 of the digits 0 through 9. The digits may repeat. Which of the following expressions gives the number of different 6-character codes that are possible?F. 1(1)(10)(10)(10)(10) G. 2(1)(10)(9)(8)(7) H. 2(1)(10)(10)(10)(10) J. 2(2)(10)(9)(8)(7) K. 2(2)(10)(10)(10)(10) InfoInstr123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960 Flag
Solution
The correct answer is F. 1(1)(10)(10)(10)(10).
Here's the step-by-step explanation:
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The first character is always the letter 'A', so there's only 1 possibility for the first character.
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The second character is always the letter 'H', so there's only 1 possibility for the second character as well.
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The next four characters are digits from 0 to 9. Since the digits can repeat, there are 10 possibilities (0-9) for each of the four characters.
So, the total number of different 6-character codes that are possible is 1 (for 'A') * 1 (for 'H') * 10 (for the third character) * 10 (for the fourth character) * 10 (for the fifth character) * 10 (for the sixth character) = 10,000.
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