A letter lock consists of 4 rings, each ring contains 9 non-zero digits. This lock can be opened by setting a 4 digit code with the proper combination of each of the 4 rings Maximum how many codes can be formed to open the lock?
Question
A letter lock consists of 4 rings, each ring contains 9 non-zero digits. This lock can be opened by setting a 4 digit code with the proper combination of each of the 4 rings Maximum how many codes can be formed to open the lock?
Solution
The number of codes that can be formed to open the lock is determined by the number of possibilities for each ring. Since each ring contains 9 non-zero digits, there are 9 possibilities for each ring.
Since there are 4 rings, you multiply the number of possibilities for each ring together to get the total number of possible codes.
So, the calculation would be:
9 (possibilities for ring 1) * 9 (possibilities for ring 2) * 9 (possibilities for ring 3) * 9 (possibilities for ring 4)
= 6561 possible codes.
Therefore, a maximum of 6561 codes can be formed to open the lock.
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