This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.Tutorial ExerciseFor what value of the constant c is the function f continuous on (−∞, ∞)?f(x) = cx2 + 5x if x < 6x3 − cx if x ≥ 6Part 1 of 2Note that f is continuous on (−∞, 6) and (6, ∞). For the function to be continuous on (−∞, ∞), we need to ensure that as x approaches 6, the left and right limits match.First we find the left limit.lim x→6− f(x) = lim x→6− (cx2 + 5x) = Next, we find the right limit.lim x→6+ f(x) = lim x→6+ (x3 − cx) =
Question
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.Tutorial ExerciseFor what value of the constant c is the function f continuous on (−∞, ∞)?f(x) = cx2 + 5x if x < 6x3 − cx if x ≥ 6Part 1 of 2Note that f is continuous on (−∞, 6) and (6, ∞). For the function to be continuous on (−∞, ∞), we need to ensure that as x approaches 6, the left and right limits match.First we find the left limit.lim x→6− f(x) = lim x→6− (cx2 + 5x) = Next, we find the right limit.lim x→6+ f(x) = lim x→6+ (x3 − cx) =
Solution
To find the left limit, we substitute x = 6 into the equation for x < 6:
lim x→6− (cx² + 5x) = c(6)² + 5(6) = 36c + 30
Next, we find the right limit by substituting x = 6 into the equation for x ≥ 6:
lim x→6+ (x³ - cx) = (6)³ - c(6) = 216 - 6c
For the function to be continuous at x = 6, the left and right limits must be equal. Therefore, we set the two limits equal to each other and solve for c:
36c + 30 = 216 - 6c
This simplifies to:
42c = 186
So, c = 186 / 42 = 4.42857
Therefore, the function f is continuous on (-∞, ∞) when c = 4.42857.
Similar Questions
Find each x-value at which f is discontinuous and for each x-value, determine whether f is continuous from the right, or from the left, or neither.f(x) = x + 6 if x < 0 ex if 0 ≤ x ≤ 1 6 − x if x > 1x = (smaller value)continuous from the rightcontinuous from the left neitherx = (larger value)continuous from the rightcontinuous from the left neither
f (x) ={ 1x−1 if x 6 = 1;0 if x = 1.(a) Does limx→5f (x) exist? If so, what is it? Try and establish thevalidity of your answer formally using an epsilon-delta argument.If it exists, does it equal f (5)? Is this function continuous at thepoint x = 5?(b) Does limx→1f (x) exist? If so, what is it? Try and establish thevalidity of your answer formally using an epsilon-delta argument.If it exists, does it equal f (1)? Is this function continuous at thepoint x = 1?(c) Is this function continuous?2. Consider the functionf (x) ={x2 if x 6 = 0;−50 if x = 0.2
Let f (x) be defined by: f (x) = 2x /(3 + x) , x ≤ −2 k(x − 2), −2 < x < 4 2x − 6, x ≥ 4 Which of the following values of k would make f (x) continuous on R? a) k = 2 (b) k = 1 (c) There is no such value for k. (d) k = −1
Show that the function given below is continuous at x=−6 . \[ f(x)=\left\{\begin{array}{ll} \frac{3 x^{2}+17 x-6}{x+6} & x \neq-6 \\ -19 & x=-6 \end{array}\right. \] The function f(x) is continuous at x=−6 since f(−6)= and x→−6 lim f(x)= implies that x→−6 lim f(x)∣f(−6)
From the graph of f, state each x-value at which f is discontinuous. For each x-value, determine whether f is continuous from the right, or from the left, or neither. (Enter your answers from smallest to largest.)x = (smallest value)continuous from the rightcontinuous from the left neitherx = continuous from the rightcontinuous from the left neitherx = continuous from the rightcontinuous from the left neitherx = (largest value)continuous from the rightcontinuous from the left neither
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.