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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.Tutorial ExerciseFor what value of the constant c is the function f continuous on (−∞, ∞)?f(x) =   cx2 + 5x      if x < 6x3 − cx if x ≥ 6Part 1 of 2Note that f is continuous on (−∞, 6) and (6, ∞). For the function to be continuous on (−∞, ∞), we need to ensure that as x approaches 6, the left and right limits match.First we find the left limit.lim x→6− f(x) = lim x→6− (cx2 + 5x) = Next, we find the right limit.lim x→6+ f(x) = lim x→6+ (x3 − cx) =

Question

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.Tutorial ExerciseFor what value of the constant c is the function f continuous on (−∞, ∞)?f(x) =   cx2 + 5x      if x < 6x3 − cx if x ≥ 6Part 1 of 2Note that f is continuous on (−∞, 6) and (6, ∞). For the function to be continuous on (−∞, ∞), we need to ensure that as x approaches 6, the left and right limits match.First we find the left limit.lim x→6− f(x) = lim x→6− (cx2 + 5x) = Next, we find the right limit.lim x→6+ f(x) = lim x→6+ (x3 − cx) =

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Solution

To find the left limit, we substitute x = 6 into the equation for x < 6:

lim x→6− (cx² + 5x) = c(6)² + 5(6) = 36c + 30

Next, we find the right limit by substituting x = 6 into the equation for x ≥ 6:

lim x→6+ (x³ - cx) = (6)³ - c(6) = 216 - 6c

For the function to be continuous at x = 6, the left and right limits must be equal. Therefore, we set the two limits equal to each other and solve for c:

36c + 30 = 216 - 6c

This simplifies to:

42c = 186

So, c = 186 / 42 = 4.42857

Therefore, the function f is continuous on (-∞, ∞) when c = 4.42857.

This problem has been solved

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