You are given two integer arrays nums1 and nums2.From nums1 two elements have been removed, and all other elements have been increased (or decreased in the case of negative) by an integer, represented by the variable x.As a result, nums1 becomes equal to nums2. Two arrays are considered equal when they contain the same integers with the same frequencies.Return the minimum possible integer x that achieves this equivalence. Example 1:Input: nums1 = [4,20,16,12,8], nums2 = [14,18,10]Output: -2Explanation:After removing elements at indices [0,4] and adding -2, nums1 becomes [18,14,10].Example 2:Input: nums1 = [3,5,5,3], nums2 = [7,7]Output: 2Explanation:After removing elements at indices [0,3] and adding 2, nums1 becomes [7,7]. Constraints:3 <= nums1.length <= 200nums2.length == nums1.length - 20 <= nums1[i], nums2[i] <= 1000The test cases are generated in a way that there is an integer x such that nums1 can become equal to nums2 by removing two elements and adding x to each element of nums1.
Question
You are given two integer arrays nums1 and nums2.From nums1 two elements have been removed, and all other elements have been increased (or decreased in the case of negative) by an integer, represented by the variable x.As a result, nums1 becomes equal to nums2. Two arrays are considered equal when they contain the same integers with the same frequencies.Return the minimum possible integer x that achieves this equivalence. Example 1:Input: nums1 = [4,20,16,12,8], nums2 = [14,18,10]Output: -2Explanation:After removing elements at indices [0,4] and adding -2, nums1 becomes [18,14,10].Example 2:Input: nums1 = [3,5,5,3], nums2 = [7,7]Output: 2Explanation:After removing elements at indices [0,3] and adding 2, nums1 becomes [7,7]. Constraints:3 <= nums1.length <= 200nums2.length == nums1.length - 20 <= nums1[i], nums2[i] <= 1000The test cases are generated in a way that there is an integer x such that nums1 can become equal to nums2 by removing two elements and adding x to each element of nums1.
Solution
To solve this problem, you can follow these steps:
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First, sort both arrays in ascending order. This will make it easier to compare the elements of the two arrays.
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Then, iterate over the elements of the first array. For each element, calculate the difference between it and the corresponding element in the second array. This difference is a candidate for the value of x.
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Keep track of the minimum difference you have found so far. This will be the minimum possible value of x.
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However, you also need to check if removing two elements from the first array can make it equal to the second array. To do this, you can iterate over all pairs of elements in the first array, remove them, and then check if the resulting array is equal to the second array. If it is, update the minimum value of x accordingly.
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Finally, return the minimum value of x.
Here is a Python code snippet that implements this algorithm:
def min_x(nums1, nums2):
nums1.sort()
nums2.sort()
min_x = float('inf')
for i in range(len(nums1)):
x = nums2[i] - nums1[i]
temp = nums1[:i] + nums1[i+2:]
temp = [num + x for num in temp]
temp.sort()
if temp == nums2:
min_x = min(min_x, x)
return min_x
This function works by first sorting the input arrays, then iterating over the elements of the first array and calculating the difference between each element and the corresponding element in the second array. It keeps track of the minimum difference found so far, and checks if removing two elements from the first array can make it equal to the second array. If it can, it updates the minimum difference accordingly. Finally, it returns the minimum difference.
Similar Questions
You are given two arrays of equal length, nums1 and nums2.Each element in nums1 has been increased (or decreased in the case of negative) by an integer, represented by the variable x.As a result, nums1 becomes equal to nums2. Two arrays are considered equal when they contain the same integers with the same frequencies.Return the integer x. Example 1:Input: nums1 = [2,6,4], nums2 = [9,7,5]Output: 3Explanation:The integer added to each element of nums1 is 3.Example 2:Input: nums1 = [10], nums2 = [5]Output: -5Explanation:The integer added to each element of nums1 is -5.Example 3:Input: nums1 = [1,1,1,1], nums2 = [1,1,1,1]Output: 0Explanation:The integer added to each element of nums1 is 0. Constraints:1 <= nums1.length == nums2.length <= 1000 <= nums1[i], nums2[i] <= 1000The test cases are generated in a way that there is an integer x such that nums1 can become equal to nums2 by adding x to each element of nums1.
You are given two integers n and x. You have to construct an array of positive integers nums of size n where for every 0 <= i < n - 1, nums[i + 1] is greater than nums[i], and the result of the bitwise AND operation between all elements of nums is x.Return the minimum possible value of nums[n - 1]. Example 1:Input: n = 3, x = 4Output: 6Explanation:nums can be [4,5,6] and its last element is 6.Example 2:Input: n = 2, x = 7Output: 15Explanation:nums can be [7,15] and its last element is 15. Constraints:1 <= n, x <= 108
You are given a sorted array of integers. Write a program that implements a binary search algorithm to find the element with the minimum difference from the given target.Note: This question was asked in CTS coding test.Input format :The first line input consists of an integer N, representing the number of array elements.The second line consists of N space-separated integers, representing the sorted array elements.The third line consists of an integer representing the target element.Output format :The output prints an integer representing the element with the minimum difference from the given target.
You are given two 0-indexed integer arrays nums1 and nums2 of sizes n and m, respectively.Consider calculating the following values:The number of indices i such that 0 <= i < n and nums1[i] occurs at least once in nums2.The number of indices i such that 0 <= i < m and nums2[i] occurs at least once in nums1.Return an integer array answer of size 2 containing the two values in the above order.
You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively.Merge nums1 and nums2 into a single array sorted in non-decreasing order.The final sorted array should not be returned by the function, but instead be stored inside the array nums1. To accommodate this, nums1 has a length of m + n, where the first m elements denote the elements that should be merged, and the last n elements are set to 0 and should be ignored. nums2 has a length of n. Example 1:Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3Output: [1,2,2,3,5,6]Explanation: The arrays we are merging are [1,2,3] and [2,5,6].The result of the merge is [1,2,2,3,5,6] with the underlined elements coming from nums1.Example 2:Input: nums1 = [1], m = 1, nums2 = [], n = 0Output: [1]Explanation: The arrays we are merging are [1] and [].The result of the merge is [1].Example 3:Input: nums1 = [0], m = 0, nums2 = [1], n = 1Output: [1]Explanation: The arrays we are merging are [] and [1].The result of the merge is [1].Note that because m = 0, there are no elements in nums1. The 0 is only there to ensure the merge result can fit in nums1. Constraints:nums1.length == m + nnums2.length == n0 <= m, n <= 2001 <= m + n <= 200-109 <= nums1[i], nums2[j] <= 109 Follow up: Can you come up with an algorithm that runs in O(m + n) time?
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