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A person jumped out of a plane and began falling to the surface of the Earth at a rate of 9.8 m/s².The person and their equipment have a total mass of 95 kg.After 30 seconds they have reached a speed of 50 m/s.Calculate the kinetic energy store of the person and their equipment at this moment.

Question

A person jumped out of a plane and began falling to the surface of the Earth at a rate of 9.8 m/s².The person and their equipment have a total mass of 95 kg.After 30 seconds they have reached a speed of 50 m/s.Calculate the kinetic energy store of the person and their equipment at this moment.

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Solution 1

To calculate the kinetic energy, we can use the formula:

Kinetic Energy = 0.5 * mass * velocity²

Given in the problem, the mass (m) is 95 kg and the velocity (v) is 50 m/s.

Substituting these values into the formula, we get:

Kinetic Energy = 0.5 * 95 kg * (50 m/s)²

First, square the velocity:

50 m/s * 50 m/s = 2500 (m²/s²)

Then multiply this by the mass and 0.5:

0.5 * 95 kg * 2500 m²/s² = 118750 Joules

So, the kinetic energy store of the person and their equipment at this moment is 118750 Joules.

This problem has been solved

Solution 2

To calculate the kinetic energy of the person and their equipment, we can use the formula for kinetic energy:

KE = 0.5 * m * v²

where:

  • KE is the kinetic energy,
  • m is the mass of the object (in this case, the person and their equipment), and
  • v is the velocity of the object.

Given in the problem, m = 95 kg and v = 50 m/s. Substituting these values into the formula gives:

KE = 0.5 * 95 kg * (50 m/s)² KE = 0.5 * 95 kg * 2500 m²/s² KE = 118750 Joules

So, the kinetic energy store of the person and their equipment at this moment is 118750 Joules.

This problem has been solved

Solution 3

To calculate the kinetic energy, we can use the formula:

KE = 0.5 * m * v²

where: KE is the kinetic energy, m is the mass (in kg), and v is the velocity (in m/s).

Given in the problem, m = 95 kg and v = 50 m/s.

Substituting these values into the formula, we get:

KE = 0.5 * 95 kg * (50 m/s)² KE = 0.5 * 95 kg * 2500 m²/s² KE = 0.5 * 237500 kg*m²/s² KE = 118750 Joules

So, the kinetic energy store of the person and their equipment at this moment is 118750 Joules.

This problem has been solved

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