The integral of a function in the form of ∫x^n dx is (x^(n+1))/(n+1) + C, where C is the constant of integration.

In this case, the function to be integrated is 20x^2.

So, applying the formula, we get:

= (20*x^(2+1))/(2+1) + C
= (20*x^3)/3 + C
= 20/3 * x^3 + C

So, none of the options A, B, C, D is correct. The correct answer should be 20/3 * x^3 + C.

Question

The integral of a function in the form of ∫x^n dx is (x^(n+1))/(n+1) + C, where C is the constant of integration.

In this case, the function to be integrated is 20x^2.

So, applying the formula, we get:

= (20*x^(2+1))/(2+1) + C
= (20*x^3)/3 + C
= 20/3 * x^3 + C

So, none of the options A, B, C, D is correct. The correct answer should be 20/3 * x^3 + C.

Knowee AI · Accepted Answer

The integral of a function in the form of ∫x^n dx is (x^(n+1))/(n+1) + C, where C is the constant of integration.

In this case, the function to be integrated is 20x^2.

So, applying the formula, we get:

= (20*x^(2+1))/(2+1) + C
= (20*x^3)/3 + C
= 20/3 * x^3 + C

So, none of the options A, B, C, D is correct. The correct answer should be 20/3 * x^3 + C.

Evaluate∫20x2dx∫20𝑥2𝑑𝑥Select one:A.203x3+C203𝑥3+𝐶B.10x3+C10𝑥3+𝐶C.−152x3+C−152𝑥3+𝐶D.−203x3+C