If the dimension of (Angle × Force × Length) is M n1 L n2 T  n3  then the value of (n 1 , n 2 , n 3 ) is                (a)  (1, 1, –1)  (b)  (1. 2, –2) (c)  (1, 1, 1)  (d)  (1, 2, 2)

To solve this problem, we need to understand the dimensions of each of the quantities given and then equate them to the dimensions provided in the question.

1. Angle: Angle is a dimensionless quantity. It does not have any dimensions of mass, length, or time. So, its dimensions are M^0 L^0 T^0.

2. Force: The dimension of force is given by Newton's second law, F = ma. Here, m has the dimension of mass (M^1), and a has the dimension of length/time^2 (L^1 T^-2). So, the dimensions of force are M^1 L^1 T^-2.

3. Length: The dimension of length is simply L^1.

Now, multiplying these dimensions together, we get:

(M^0 L^0 T^0) * (M^1 L^1 T^-2) * (L^1) = M^1 L^2 T^-2.

Comparing this with the dimensions given in the question, M^n1 L^n2 T^n3, we can see that n1 = 1, n2 = 2, and n3 = -2.

So, the correct answer is (b) (1, 2, -2).