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(2x−1)(3x 2 +4x−10)

Question

(2x−1)(3x 2 +4x−10)

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Solution

Sure, let's solve this step by step:

First, let's distribute the terms:

= 2x * (3x^2) + 2x * (4x) + 2x * (-10) - 1 * (3x^2) - 1 * (4x) - 1 * (-10)

= 6x^3 + 8x^2 - 20x - 3x^2 - 4x + 10

Now, let's combine like terms:

= 6x^3 + (8x^2 - 3x^2) + (-20x - 4x) + 10

= 6x^3 + 5x^2 - 24x + 10

So, (2x−1)(3x^2 +4x−10) simplifies to 6x^3 + 5x^2 - 24x + 10.

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