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(2x+3)(2x−7) 2 −(2x−7)(4x−5)

Question

(2x+3)(2x−7) 2 −(2x−7)(4x−5)

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Solution

First, let's expand the brackets:

(2x+3)(2x−7) = 4x^2 - 14x + 6x - 21 = 4x^2 - 8x - 21

(2x−7)(4x−5) = 8x^2 - 20x - 28x + 35 = 8x^2 - 48x + 35

Now, let's subtract the second equation from the first one:

(4x^2 - 8x - 21) - (8x^2 - 48x + 35) = 4x^2 - 8x^2 - 8x + 48x - 21 - 35 = -4x^2 + 40x - 56

So, the answer is -4x^2 + 40x - 56.

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