Expressx(1 − 2x)2(1 − 3x)in partial fractions.
Question
Expressx(1 − 2x)2(1 − 3x)in partial fractions.
Solution
To express the given function in partial fractions, we first need to factorize the denominator. However, in this case, the denominator is already factorized as (1 - 2x) and (1 - 3x).
The general form of the partial fraction decomposition for this function is:
x/(1 - 2x)(1 - 3x) = A/(1 - 2x) + B/(1 - 3x)
where A and B are constants that we need to find.
To find A and B, we can use the method of equating coefficients.
First, we clear the fractions by multiplying both sides by the common denominator (1 - 2x)(1 - 3x):
x = A(1 - 3x) + B(1 - 2x)
Now, we can equate the coefficients on both sides of the equation to find A and B.
For the x term:
0 = -3A - 2B
For the constant term:
1 = A + B
Solving these two equations simultaneously, we get A = 2 and B = -1.
So, the partial fraction decomposition of the given function is:
x/(1 - 2x)(1 - 3x) = 2/(1 - 2x) - 1/(1 - 3x)
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