Netflix: A study conducted by a technology company showed that the mean time spent per day browsing the video streaming service Netflix for something to watch was 19.9 minutes. Assume the standard deviation is =σ6. Suppose a simple random sample of 103 visits taken this year has a sample mean of =x20.9 minutes. A social scientist is interested to know whether the mean time browsing Netflix has increased. Use the =α0.01 level of significance and the P-value method with the TI-84 Plus calculator.Part 1 of 5(a) State the appropriate null and alternate hypotheses.H0: =μ19.9H1: >μ19.9This hypothesis test is a ▼right-tailed test.Part: 1 / 51 of 5 Parts CompletePart 2 of 5(b) Compute the value of the test statistic. Round the answer to two decimal places.z=

At one school, the average amount of time that tenth-graders spend watching television each week is 18.4 hours. The principal introduces a campaign to encourage the students to watch less television. One year later, the principal wants to perform a hypothesis test to determine whether the average amount of time spent watching television per week has decreased. Formulate the null and alternative hypotheses for the study described.Question 17Answera.H0: µ = 18.4 ; H1 µ ≠18.4b.H0: µ < 18.4 ; H1 µ > 18.4c.H0: µ = 18.4 ; H1 µ <18.4d.H0: µ > 18.4 ; H1 µ <18.4

A study was conducted to estimate μ, the mean number of weekly hours that U.S. adults use computers at home. Suppose a random sample of 81 U.S. adults gives a mean weekly computer usage time of 8.5 hours and that from prior studies, the population standard deviation is assumed to be σ = 3.6 hours.A similar study conducted a year earlier estimated that μ, the mean number of weekly hours that U.S. adults use computers at home, was 8 hours. We would like to test (at the usual significance level of 5%) whether the current study provides significant evidence that this mean has changed since the previous year.Using a 95% confidence interval of (7.7, 9.3), which of the following is an appropriate conclusion? The current study does provide significant evidence that the mean number of weekly hours has changed over the past year, since 8 falls outside the confidence interval. The current study does not provide significant evidence that the mean number of weekly hours has changed over the past year, since 8 falls outside the confidence interval. The current study does provide significant evidence that the mean number of weekly hours has changed over the past year, since 8 falls inside the confidence interval. The current study does not provide significant evidence that the mean number of weekly hours has changed over the past year, since 8 falls inside the confidence interval. You cannot draw a conclusion because the only way to reach a conclusion is to find the p-value of the test.

Suppose that the bollywood movie industry wants to know how often college students go to the movies. Sixteen college students are selected at random from a city and asked how many movies they have seen in theater in the previous year. The data are as follows: 7, 13, 0, 10, 2, 8, 4, 11, 0, 5, 16, 6, 2, 12, 9, 0. Suppose that the national average for movie visits per person in a year is 9.0 and standard deviation is 4.0. a. State the NULL and Alternative hypothesis.b. Test statistically whether college students' habit of watching movie in theatre is significantly different from the population? The 95% region of acceptance for the test-statistic is [-1.96 : 1.96].

A company decided to test the hypothesis that the average time a company’s employees are spending to check their private e-mails at work is more than 9 minutes. A random sample of 50 employees were selected and they averaged 9.6 minutes. It is believed that the population standard deviation is 2.5 minutes. The α is set to 0.05. The p-value for this hypothesis test would be __________.

Are you smarter than a second grader? A random sample of 70 second graders in a certain school district are given a standardized mathematics skills test. The sample mean score is =x55. Assume the standard deviation of test scores is =σ21. The nationwide average score on this test is 50. The school superintendent wants to know whether the second graders in her school district have greater math skills than the nationwide average. Use the =α0.05 level of significance and the P-value method with the TI-84 Plus calculator.Part 1 of 5(a) State the appropriate null and alternate hypotheses.:H0  =μ50:H1  >μ50This hypothesis test is a ▼right-tailed test.Part 2 of 5(b) Compute the value of the test statistic. Round the answer to two decimal places.z=1.9Correct Answer:=z1.99Part: 2 / 52 of 5 Parts CompletePart 3 of 5(c) Compute the P-value of the test statistic. Round the answer to four decimal places.P-value=Skip PartCheckSave For LaterSubmit Assignment