At one school, the average amount of time that tenth-graders spend watching television each week is 18.4 hours. The principal introduces a campaign to encourage the students to watch less television. One year later, the principal wants to perform a hypothesis test to determine whether the average amount of time spent watching television per week has decreased. Formulate the null and alternative hypotheses for the study described.Question 17Answera.H0: µ = 18.4 ; H1 µ ≠18.4b.H0: µ < 18.4 ; H1 µ > 18.4c.H0: µ = 18.4 ; H1 µ <18.4d.H0: µ > 18.4 ; H1 µ <18.4

Netflix: A study conducted by a technology company showed that the mean time spent per day browsing the video streaming service Netflix for something to watch was 20.6 minutes. Assume the standard deviation is =σ8. Suppose a simple random sample of 102 visits taken this year has a sample mean of =x19.6 minutes. A social scientist is interested to know whether the mean time browsing Netflix has decreased. Use the =α0.05 level of significance and the P-value method with the TI-84 Plus calculator.Part 1 of 5(a) State the appropriate null and alternate hypotheses.H0: =μ20.6H1: <μ20.6This hypothesis test is a ▼left-tailed test.Part 2 of 5(b) Compute the value of the test statistic. Round the answer to two decimal places.z=−1.26Part 3 of 5(c) Compute the P-value. Round the answer to four decimal places.P-value=0.1038Part: 3 / 53 of 5 Parts CompletePart 4 of 5(d) Determine whether to reject H0. Use the =α0.05 level of significance.▼(Choose one) H0 at the =α0.05 level.

The manager of a mall conducted a survey among two groups (n1 = 100, n2 = 100) of visitors to the mall on different days. She found that the first group spent an average of 60 minutes in the mall, while the second group spent an average of 90 minutes in the mall.If the manager wishes to see the difference in the average times spent by the two groups in the mall, which of the following sets shows the null hypothesis and alternative hypothesis?Null Hypothesis: There is at least some difference in the average times spent by the two groups in the mall.Alternative Hypothesis: The difference in the average times spent by the two groups in the mall is 30 minutes.Null Hypothesis: There is no difference in the average times spent by the two groups in the mall.Alternative Hypothesis: There is at least some difference in the average times spent by the two groups in the mall.Null Hypothesis: There is at least some difference in the average times spent by the two groups in the mall.Alternative Hypothesis: There is no difference in the average times spent by the two groups in the mall.Null Hypothesis: There is no difference in the average times spent by the two groups in the mall.Alternative Hypothesis: There is a difference in the average times spent by the two groups in the mall, with a standard deviation of 30 minutes.

The amount of television viewed by today's youth is of primary concern to Parents Against Watching Television (PAWT). 300 parents of elementary school-aged children were asked to estimate the number of hours per week that their child watches television. The mean and the standard deviation for their responses were 12 and 2, respectively. PAWT constructed a stem-and-leaf display for the data that showed that the distribution of times was a symmetric, mound-shaped distribution. Give an interval where you believe approximately 95% of the television viewing times fell in the distribution.Group of answer choicesless than 16less than 10 and more than 14 hours per weekbetween 8 and 16 hours per weekbetween 6 and 18 hours per week

In the past, the mean running time for a certain type of flashlight battery has been 8.0 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has increased as a result. The hypotheses are:H0 : μ < 8.0 hoursH1 : μ > 8.0 hoursExplain the meaning of a Type II error.Question 2Answera.Concluding that μ > 8.0 hoursb.Failing to reject the hypothesis that μ = 8.0 hours when in fact μ = 8.0 hoursc.Concluding that μ > 8.0 hours when in fact μ > 8.0 hoursd.Failing to reject the hypothesis that μ < 8.0 hours when in fact μ > 8.0 hours

Do TV viewers differ, on average, in terms of the amount of television that they watch during the month of January as opposed to June? A researcher conducted a hypothetical study, where the she randomly selected 50 TV viewers and recorded the number of minutes of television watched during January and then again in July. The researcher wanted to determine whether there is a difference in mean number of minutes of television viewing in January and in July.What hypothesis testing technique should the researcher use to analyze the data? Two-sample t-test Paired t-test ANOVA z-test for the population mean