Let's denote the two numbers as x and y.

According to the problem, we have two equations:

1) The difference between two numbers is 5, which can be written as:
x - y = 5

2) Six times of the smaller lacks by 6 from the four times of the greater. This can be written as:
4x - 6y = 6

Now, we can solve these two equations to find the values of x and y.

First, multiply the first equation by 6 to make the coefficients of y in both equations the same:

6x - 6y = 30

Now, subtract the second equation from the first:

6x - 4x = 30 - 6
2x = 24
x = 24 / 2
x = 12

Substitute x = 12 into the first equation:

12 - y = 5
y = 12 - 5
y = 7

So, the two numbers are 12 and 7.

Question

Let's denote the two numbers as x and y.

According to the problem, we have two equations:

1) The difference between two numbers is 5, which can be written as:
x - y = 5

2) Six times of the smaller lacks by 6 from the four times of the greater. This can be written as:
4x - 6y = 6

Now, we can solve these two equations to find the values of x and y.

First, multiply the first equation by 6 to make the coefficients of y in both equations the same:

6x - 6y = 30

Now, subtract the second equation from the first:

6x - 4x = 30 - 6
2x = 24
x = 24 / 2
x = 12

Substitute x = 12 into the first equation:

12 - y = 5
y = 12 - 5
y = 7

So, the two numbers are 12 and 7.

Knowee AI · Accepted Answer