Consider the following reactions.2Cu2O(s)+Cu2S(s)Δ→P(s)+Q(g)2Cu2O(s)+Cu2S(s)→ΔPs+QgDry slaked lime + R(g) → Salt used as an oxidising agent (s) + H2OMnO2 + T →  MnCl2 + 2H2O + ‘R’Al2O3 + T →  AlCl3 + UNow, choose the correct option(s)One/More correct answer(s)A.When ‘P’ is heated in air, it combines with oxygen to give a black oxide whereas gas ‘Q’ is released during thermal decomposition of ferrous sulphateB.Gas ‘R’ is released during photolytic decomposition of silver bromide, U is one of the products of neutralisation reactionC.The compound formed by the reaction of ‘U’ and sodium, turns phenolphthalein pink and the colour of aqueous solution of salt ‘PSO4’ is blueD.‘T’ reacts with baking soda to give salt, water and a gas which turns lime water milky and ‘P’ does not react with dilute ‘T’

The question seems to be a complex chemistry problem involving multiple reactions and the identification of unknown substances. Let's break it down step by step:

1. The first reaction is: 2Cu2O(s)+Cu2S(s)Δ→P(s)+Q(g). From this reaction, we can infer that P is a solid and Q is a gas. The question states that when P is heated in air, it combines with oxygen to give a black oxide. This suggests that P could be Copper (Cu), as copper forms a black oxide when heated in air. The gas Q is released during thermal decomposition of ferrous sulphate, which is SO2. So, option A seems correct.

2. The second reaction is: Dry slaked lime + R(g) → Salt used as an oxidising agent (s) + H2O. The gas R is released during photolytic decomposition of silver bromide. This gas could be Br2. The product U is one of the products of neutralisation reaction, which could be a salt or water. So, option B seems correct.

3. The third reaction is: MnO2 + T → MnCl2 + 2H2O + ‘R’. The compound formed by the reaction of ‘U’ and sodium, turns phenolphthalein pink. This suggests that U could be a base, as bases turn phenolphthalein pink. The colour of aqueous solution of salt ‘PSO4’ is blue, which suggests that P could be Cu, as copper sulfate is blue. So, option C seems correct.

4. The fourth reaction is: Al2O3 + T → AlCl3 + U. ‘T’ reacts with baking soda to give salt, water and a gas which turns lime water milky. This suggests that T could be an acid, as acids react with baking soda to produce CO2, which turns lime water milky. ‘P’ does not react with dilute ‘T’, which further suggests that P could be Cu, as copper does not react with dilute acids. So, option D seems correct.

Therefore, all options A, B, C, and D seem to be correct.