The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); ans. 5 5 7 7 6 6 7 6 5 7 6 7
Question
The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i);
ans. 5 5 7
7 6 6
7 6 5
7 6 7
Solution
The output of the code is undefined. The order of evaluation of function arguments is not specified in the C language standard, so it can vary between different compilers and even different runs of the same compiler. Therefore, the output could be any of the four options, or something else entirely. It's generally considered bad practice to write code that depends on the order of evaluation of function arguments.
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