What is the solution to this equation?2(40−5y)=10y+5(1−y)2(40-5𝑦)=10𝑦+5(1-𝑦)
Question
What is the solution to this equation?2(40−5y)=10y+5(1−y)2(40-5𝑦)=10𝑦+5(1-𝑦)
Solution
Sure, let's solve the equation step by step:
The given equation is: 2(40−5y)=10y+5(1−y)
Step 1: Distribute the numbers outside the parentheses on both sides of the equation:
80 - 10y = 10y + 5 - 5y
Step 2: Simplify both sides of the equation:
80 - 10y = 5y + 5
Step 3: Move all the y terms to one side of the equation and the constants to the other side:
10y + 5y = 80 - 5
Step 4: Simplify both sides of the equation:
15y = 75
Step 5: Divide both sides of the equation by 15 to solve for y:
y = 75 / 15
So, the solution to the equation is y = 5.
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