How many particles of NH4NO3 are in 0.94 L of 0.9 M solution?

To find the number of particles of NH4NO3 in a 0.94 L of 0.9 M solution, we need to follow these steps:

1. First, we need to find the number of moles in the solution. The molarity (M) is defined as the number of moles of solute per liter of solution. So, we can find the number of moles by multiplying the volume of the solution by the molarity.

   Number of moles = Molarity * Volume Number of moles = 0.9 moles/L * 0.94 L = 0.846 moles

2. Next, we need to find the number of particles. We can do this by using Avogadro's number, which states that one mole of any substance contains 6.022 x 10^23 particles.

   Number of particles = Number of moles * Avogadro's number Number of particles = 0.846 moles * 6.022 x 10^23 particles/mole = 5.09 x 10^23 particles

So, there are approximately 5.09 x 10^23 particles of NH4NO3 in a 0.94 L of 0.9 M solution.