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Consider the reaction represented by the following equation:4NH3+5O2→4NO+6H2O4NH3+5𝑂2→4NO+6𝐻2𝑂 How many moles of O2𝑂2  is required for every 7.617.61  mol of  NH3NH3 that reacts? 30.4mol30.4mol 7.61mol7.61mol 9.51mol9.51mol 6.09mol6.09mol 38.0mol38.0mol

Question

Consider the reaction represented by the following equation:4NH3+5O2→4NO+6H2O4NH3+5𝑂2→4NO+6𝐻2𝑂 How many moles of O2𝑂2  is required for every 7.617.61  mol of  NH3NH3 that reacts? 30.4mol30.4mol 7.61mol7.61mol 9.51mol9.51mol 6.09mol6.09mol 38.0mol38.0mol

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Solution

The balanced chemical equation shows that 5 moles of O2 are required for every 4 moles of NH3.

To find out how many moles of O2 are required for 7.61 moles of NH3, you can set up a proportion as follows:

4 moles NH3 / 5 moles O2 = 7.61 moles NH3 / x moles O2

Solving for x gives you:

x = (5 moles O2 / 4 moles NH3) * 7.61 moles NH3

x = 9.51 moles O2

So, 9.51 moles of O2 are required for every 7.61 moles of NH3 that reacts.

This problem has been solved

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