The V-I characteristic of a certain tunnel diode shows that the current changes from 0.25 mA to 0.15 mA when the voltage changes from 125 mV to 200 mV. What is the resistance?
Question
The V-I characteristic of a certain tunnel diode shows that the current changes from 0.25 mA to 0.15 mA when the voltage changes from 125 mV to 200 mV. What is the resistance?
Solution
To find the resistance, we can use Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I).
First, we need to calculate the change in voltage (ΔV) and the change in current (ΔI).
ΔV = 200 mV - 125 mV = 75 mV ΔI = 0.15 mA - 0.25 mA = -0.1 mA
Next, we convert the values to SI units: ΔV = 75 mV = 0.075 V ΔI = -0.1 mA = -0.0001 A
Now, we can calculate the resistance using Ohm's Law: R = ΔV / ΔI
R = 0.075 V / -0.0001 A
Finally, we can calculate the resistance: R = -750 Ω
Therefore, the resistance is -750 Ω.
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