Calculate the hardness in terms of CaCO3 Equivalent if 16.8mg/l   Mg (HCO3)2  is present in water sample.a.40 mg/lb.16.8 mg/lc.11 mg/ld.11.5 mg/l

Calculate the total hardness of water in °Fr and °Cl from the following analysis of water sample. Mg(HCO3)2=20.8 mg/L, Mg(NO3)2=28.8 mg/L, MgCl2=21.0 mg/L, MgSO4=20 mg/L, CaCO3=21.2 mg/L, KCl=73.2 mg/L

Calculate the temporary hardness and permanent hardness of a sample of water containing: Mg(HCO3)2 =7.3 mg/L; Ca(HCO3)2 = 16.2 mg/L; MgCl2 = 9.5 mg/L; CaSO4 = 13.6 mg/LMolecular weights: Ca(HCO3)2 = 162; Mg(HCO3)2=146; CaSO4= 136; MgSO4 = 120; MgCl2 = 95; Al2(SO4)3 = 114;Ca(NO3)2=164

Example 1: Calculate the hardness of water sample having following analysis : Mg(HCO3)2 = 7.3ppm, Ca(HCO3)2 = 16.2 ppm, MgCl2 = 9.5 ppm, CaSO4 = 13.6 ppm, Fe2O3 = 8.5 ppm, Mg(NO3)2=14.8 ppm. Also calculate carbonate and non carbonate hardnes

A  3L water sample has a hardness of 300ppm by mass CaCO3. The grams of Calcium Carbonate CaCO3 is:Question 34Select one:a.1.0gb.0.20gc.0.30gd.1.20g

0.50 g of CaCO3 was dissolved in HCl and diluted to 500 ml. 100ml of this solution required 20 ml of EDTA solution for titration. 100 ml of hard water sample required 30 ml of the same EDTA solution for titration. On boiling, titration of 100ml of same water sample required 10 ml of EDTA. Calculate total, temporary and permanent hardness of water. 5M (1 ml of 0.01M EDTA= 1mg of CaCO3)