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The radius of a circle is same as the side of a square. Their perimeters are in the ratio

Question

The radius of a circle is same as the side of a square. Their perimeters are in the ratio

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Solution

Let's assume that the radius of the circle is "r" and the side of the square is also "r".

The formula for the perimeter of a circle is 2πr, where π is a constant approximately equal to 3.14. Therefore, the perimeter of the circle is 2πr.

The formula for the perimeter of a square is 4s, where s is the length of one side of the square. In this case, the length of one side of the square is also "r". Therefore, the perimeter of the square is 4r.

To find the ratio of their perimeters, we divide the perimeter of the circle by the perimeter of the square:

(2πr) / (4r)

Simplifying this expression, we can cancel out the common factor of "r":

2π / 4

Further simplifying, we divide both the numerator and denominator by 2:

π / 2

So, the ratio of the perimeters of the circle to the square is π/2.

This problem has been solved

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