If f(x) = x 2 + 1 and g(x) = 3x + 1, find g(20) + f(6).7498420

Sure, let's solve this step by step.

First, we need to find the values of g(20) and f(6).

For g(20), we substitute x = 20 into the function g(x) = 3x + 1:

g(20) = 3*20 + 1 = 60 + 1 = 61

Next, for f(6), we substitute x = 6 into the function f(x) = x^2 + 1:

f(6) = 6^2 + 1 = 36 + 1 = 37

Finally, we add these two results together:

g(20) + f(6) = 61 + 37 = 98