To find the coordinate matrix of x in Rn relative to the basis B', we need to solve the following system of linear equations:

8a + 7b + c = -3,
11a + 0b + 4c = 30,
0a + 10b + 6c = -18.

This system of equations can be written in matrix form as:

[8 7 1] [a] [-3]
[11 0 4] [b] = [30]
[0 10 6] [c] [-18]

We can solve this system of equations using Gaussian elimination or any other method of solving systems of linear equations.

After solving, we get the values of a, b, and c. These values form the coordinate matrix of x in Rn relative to the basis B'.

Question

To find the coordinate matrix of x in Rn relative to the basis B', we need to solve the following system of linear equations:

8a + 7b + c = -3,
11a + 0b + 4c = 30,
0a + 10b + 6c = -18.

This system of equations can be written in matrix form as:

[8 7 1] [a]   [-3]
[11 0 4] [b] = [30]
[0 10 6] [c]   [-18]

We can solve this system of equations using Gaussian elimination or any other method of solving systems of linear equations.

After solving, we get the values of a, b, and c. These values form the coordinate matrix of x in Rn relative to the basis B'.

Knowee AI · Accepted Answer

To find the coordinate matrix of x in Rn relative to the basis B', we need to solve the following system of linear equations:

8a + 7b + c = -3,
11a + 0b + 4c = 30,
0a + 10b + 6c = -18.

This system of equations can be written in matrix form as:

[8 7 1] [a]   [-3]
[11 0 4] [b] = [30]
[0 10 6] [c]   [-18]

We can solve this system of equations using Gaussian elimination or any other method of solving systems of linear equations.

After solving, we get the values of a, b, and c. These values form the coordinate matrix of x in Rn relative to the basis B'.

Find the coordinate matrix of x in Rn relative to the basis B'.B' = {(8, 11, 0), (7, 0, 10), (1, 4, 6)}, x = (−3, 30, −18)