Calculate the partial pressure (in kPa) of hydrogen in a mixture which contains 0.196 mol of hydrogen gas, 0.265 mol of oxygen gas and 0.576 mol of nitrogen gas, if the total pressure of the mixture is 549.1 kPa at 42 oC.[Reminder: 1e47 is the same as 1 x 1047]Question 22Answer107.6 kPa2905 kPa3.569e-4 kPa103.8 kPa3.442e-4 kPa
Question
Calculate the partial pressure (in kPa) of hydrogen in a mixture which contains 0.196 mol of hydrogen gas, 0.265 mol of oxygen gas and 0.576 mol of nitrogen gas, if the total pressure of the mixture is 549.1 kPa at 42 oC.[Reminder: 1e47 is the same as 1 x 1047]Question 22Answer107.6 kPa2905 kPa3.569e-4 kPa103.8 kPa3.442e-4 kPa
Solution
To calculate the partial pressure of a gas in a mixture, we use Dalton's Law of Partial Pressures. This law states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas in the mixture.
The partial pressure of a gas can be calculated using the formula:
Partial Pressure = (Moles of Gas / Total Moles of All Gases) * Total Pressure
First, we need to calculate the total moles of all gases in the mixture:
Total Moles = Moles of Hydrogen + Moles of Oxygen + Moles of Nitrogen Total Moles = 0.196 mol + 0.265 mol + 0.576 mol = 1.037 mol
Next, we can calculate the partial pressure of hydrogen:
Partial Pressure of Hydrogen = (Moles of Hydrogen / Total Moles) * Total Pressure Partial Pressure of Hydrogen = (0.196 mol / 1.037 mol) * 549.1 kPa = 103.8 kPa
So, the partial pressure of hydrogen in the mixture is 103.8 kPa.
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