Two cars C1 and C2 start their journey from two different points at 4 kmph and 3 kmph respectively and meet after 5 hours at a point where their paths make an angle of 135°. After the cars met, they interchange their paths. Each car first travels to the other car's starting point (i.e. C1 travels to C2's starting point along the path C2 was travelling on and C2 travels to C1's starting point along the path C1 was travelling on ) and then travels along the straight line path (i.e. the shortest distance) joining the starting points of the two cars, finally  reaching  it's original starting point. Find the approximate time interval between the return of C1 and C2  to their starting positions.5-6 hours11-12 hours3-4 hours8-9 hours

Two cars start from A and B and travel towards each other at the speed of 50 kmph and 60 kmph respectively. At the time of their meeting, the second car has travelled 120 km more than the first, the distance between A and B is?3120 kms1320 kms600 kms

Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.Tutorial ExerciseTwo cars start moving from the same point. One travels south at 60 mi/h and the other travels west at 25 mi/h. At what rate is the distance between the cars increasing two hours later?Part 1 of 4Using the diagram of a right triangle given below, the relation between x, y, and z isz2 = $$x2+y2 .Part 2 of 4We must find dz/dt. Differentiating both sides and simplifying gives us the following.2z · $$dzdt​  =  2x · dxdt + $$2y · dydt  dzdt =  $$1 x · dxdt + $$y · dydtPart 3 of 4After 2 hours, we have the following.z  =  x 120 2 + 502  =  70.71 130Part 4 of 4Therefore, we have the following.dzdt =  1130120 · + 50 ·   =  mi/h

Two cars P and Q start from two points A and B towards each other simultaneously. They meet for the first time 40 km from B. After meeting they exchange their speeds as well as directions and proceed to their respective starting points. On reaching their starting points, they turn back with the same speeds and meet at a point 20 km from A. Find the distance between A and B.130 km100 km120 km110 km

Car A trails car B by 150 meters. Car B travels at 50km/hr. Car C travels from the opposite direction at 30km/hr. Car C is at a distance of 320 meters from Car B. If car A decides to overtake Car B before cars B and C cross each other, what is the minimum speed at which car A must travel?