The heights of 200 adults were recorded and divided into two categories. 6’ or over Under 6’Male 12 86Female 3 Which two-way frequency table correctly shows the marginal frequencies?A. 6’ or over Under 6’ TotalMale 12 86 98Female 3 114 117Total 15 200 215B. 6’ or over Under 6’ TotalMale 12 86 100Female 3 97 100Total 15 185 200C. 6’ or over Under 6’ TotalMale 12 86 98Female 3 197 200Total 15 283 298D. 6’ or over Under 6’ TotalMale 12 86 98Female 3 99 102Total 15 185 200SUBMITarrow_backPREVIOUS
Question
The heights of 200 adults were recorded and divided into two categories. 6’ or over Under 6’Male 12 86Female 3 Which two-way frequency table correctly shows the marginal frequencies?A. 6’ or over Under 6’ TotalMale 12 86 98Female 3 114 117Total 15 200 215B. 6’ or over Under 6’ TotalMale 12 86 100Female 3 97 100Total 15 185 200C. 6’ or over Under 6’ TotalMale 12 86 98Female 3 197 200Total 15 283 298D. 6’ or over Under 6’ TotalMale 12 86 98Female 3 99 102Total 15 185 200SUBMITarrow_backPREVIOUS
Solution
The correct two-way frequency table is B.
Here's how you can calculate it:
First, add up the number of males and females in each category.
For males 6’ or over, there are 12. For males under 6’, there are 86. So the total number of males is 12 + 86 = 98.
For females 6’ or over, there are 3. The number of females under 6’ is not given, but we know that the total number of adults is 200, and we've already accounted for 98 males, so there must be 200 - 98 = 102 females.
Since we know that 3 of these females are 6’ or over, the remaining 102 - 3 = 99 must be under 6’.
So the table looks like this:
6’ or over Under 6’ Total Male 12 86 98 Female 3 99 102 Total 15 185 200
This matches option B.
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