The minimum no. of 2-input NOR gate required to make one NAND gate is

To determine the minimum number of 2-input NOR gates required to make one NAND gate, we can follow these steps:

Step 1: Understand the logic gates:

• A NOR gate is a logic gate that produces a high output only when both of its inputs are low.
• A NAND gate is a logic gate that produces a low output only when both of its inputs are high.

Step 2: Analyze the NAND gate truth table:

• A NAND gate has the following truth table:

Step 3: Determine the equivalent NOR gate expression:

• By analyzing the NAND gate truth table, we can determine the equivalent NOR gate expression as follows:

NAND = NOT (A AND B)

Step 4: Convert the NAND expression to NOR expression:

• To convert the NAND expression to NOR expression, we can use De Morgan's theorem, which states that the complement of the logical AND operation is the logical OR operation with inverted inputs.

NOR = NOT (NOT (A AND B)) = A AND B

Step 5: Determine the number of NOR gates required:

• From the NOR expression, we can see that we only need one NOR gate to implement the equivalent NAND gate.

Therefore, the minimum number of 2-input NOR gates required to make one NAND gate is 1.