To solve this problem, we need to use the concept of combinations in mathematics.

A combination is a selection of items where order does not matter. In this case, we are selecting 3 toppings out of 7 available, and it doesn't matter in what order the toppings are put on the pizza.

The formula for combinations is:

C(n, k) = n! / [k!(n-k)!]

where:
- n is the total number of items,
- k is the number of items to choose,
- "!" denotes factorial, which means multiplying all positive integers up to that number.

In this case, n is 7 (the total number of toppings) and k is 3 (the number of toppings to choose for a pizza).

So, we have:

C(7, 3) = 7! / [3!(7-3)!]
= (7*6*5*4*3*2*1) / [(3*2*1)*(4*3*2*1)]
= (7*6*5) / (3*2*1)
= 210 / 6
= 35

So, there are 35 different ways to make a pizza with 3 toppings from a selection of 7 toppings.

Question

To solve this problem, we need to use the concept of combinations in mathematics.

A combination is a selection of items where order does not matter. In this case, we are selecting 3 toppings out of 7 available, and it doesn't matter in what order the toppings are put on the pizza.

The formula for combinations is:

C(n, k) = n! / [k!(n-k)!]

where:
- n is the total number of items,
- k is the number of items to choose,
- "!" denotes factorial, which means multiplying all positive integers up to that number.

In this case, n is 7 (the total number of toppings) and k is 3 (the number of toppings to choose for a pizza).

So, we have:

C(7, 3) = 7! / [3!(7-3)!]
        = (7*6*5*4*3*2*1) / [(3*2*1)*(4*3*2*1)]
        = (7*6*5) / (3*2*1)
        = 210 / 6
        = 35

So, there are 35 different ways to make a pizza with 3 toppings from a selection of 7 toppings.

Knowee AI · Accepted Answer

To solve this problem, we need to use the concept of combinations in mathematics.

A combination is a selection of items where order does not matter. In this case, we are selecting 3 toppings out of 7 available, and it doesn't matter in what order the toppings are put on the pizza.

The formula for combinations is:

C(n, k) = n! / [k!(n-k)!]

where:
- n is the total number of items,
- k is the number of items to choose,
- "!" denotes factorial, which means multiplying all positive integers up to that number.

In this case, n is 7 (the total number of toppings) and k is 3 (the number of toppings to choose for a pizza).

So, we have:

C(7, 3) = 7! / [3!(7-3)!]
        = (7*6*5*4*3*2*1) / [(3*2*1)*(4*3*2*1)]
        = (7*6*5) / (3*2*1)
        = 210 / 6
        = 35

So, there are 35 different ways to make a pizza with 3 toppings from a selection of 7 toppings.

A pizza shop has available toppings of onions, anchovies, bacon, olives, pepperoni, mushrooms, and sausage. How many different ways can a pizza be made with 3 toppings?

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