The number of ways to choose 7 objects from 10, without replacement and where order does not matter, is given by the combination formula:

C(n, k) = n! / [k!(n-k)!]

where n is the total number of objects, k is the number of objects to choose, and '!' denotes factorial.

Here, n = 10 and k = 7. So,

C(10, 7) = 10! / [7!(10-7)!]
= 10! / [7!3!]
= (10*9*8) / (3*2*1)
= 120

So, there are 120 ways to choose 7 objects from 10.

Question

The number of ways to choose 7 objects from 10, without replacement and where order does not matter, is given by the combination formula:

C(n, k) = n! / [k!(n-k)!]

where n is the total number of objects, k is the number of objects to choose, and '!' denotes factorial.

Here, n = 10 and k = 7. So,

C(10, 7) = 10! / [7!(10-7)!]
          = 10! / [7!3!]
          = (10*9*8) / (3*2*1)
          = 120

So, there are 120 ways to choose 7 objects from 10.

Knowee AI · Accepted Answer

The number of ways to choose 7 objects from 10, without replacement and where order does not matter, is given by the combination formula:

C(n, k) = n! / [k!(n-k)!]

where n is the total number of objects, k is the number of objects to choose, and '!' denotes factorial.

Here, n = 10 and k = 7. So,

C(10, 7) = 10! / [7!(10-7)!]
          = 10! / [7!3!]
          = (10*9*8) / (3*2*1)
          = 120

So, there are 120 ways to choose 7 objects from 10.

Suppose we want to choose 7 objects, without replacement, from 10 distinct objects. How many ways can this be done, if the order of the choices does not matter?2 points120130140150