A race car track has been constructed with the a bank angle of 30.3° so there is no friction force. The race car track has a curve radius of 354 m. What speeds, for the race cars, has the track been designed to accommodate?
Question
A race car track has been constructed with the a bank angle of 30.3° so there is no friction force. The race car track has a curve radius of 354 m. What speeds, for the race cars, has the track been designed to accommodate?
Solution
To solve this problem, we can use the physics concept of banking of roads. The formula to find the speed (v) is:
v = sqrt(r * g * tan(θ))
where:
- r is the radius of the curve (354 m in this case)
- g is the acceleration due to gravity (approximately 9.8 m/s² on Earth)
- θ is the bank angle (30.3° in this case)
First, we need to convert the bank angle from degrees to radians because the trigonometric functions in most calculators use radians.
1 degree = π/180 radians
So, 30.3° = 30.3 * π/180 = 0.529 rad
Now we can substitute the values into the formula:
v = sqrt(354 m * 9.8 m/s² * tan(0.529 rad))
Calculate the value inside the square root:
= sqrt(3471.2 m²/s² * 0.636)
= sqrt(2208.67 m²/s²)
Finally, take the square root to find the speed:
v = 47 m/s
So, the track has been designed to accommodate race cars traveling at a speed of 47 m/s.
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