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The elements of a list are arranged in descending order.Which of the following two will give same outputs?   i. print(list_name.sort())   ii. print(max(list_name))   iii. print(list_name.reverse())   iv. print(list_name[-1])

Question

The elements of a list are arranged in descending order.Which of the following two will give same outputs?   i. print(list_name.sort())   ii. print(max(list_name))   iii. print(list_name.reverse())   iv. print(list_name[-1])

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Solution

The two statements that will give the same output are:

iii. print(list_name.reverse()) iv. print(list_name[-1])

Here's why:

i. print(list_name.sort()) - This will sort the list in ascending order, not descending. Also, the sort() function doesn't return anything (it returns None), so printing this will result in None.

ii. print(max(list_name)) - This will print the maximum element in the list, which is the first element in a list sorted in descending order. So, this is not the same as the last element in the list.

iii. print(list_name.reverse()) - The reverse() function doesn't return anything (it returns None), it just reverses the elements in the list. So, if the list is sorted in descending order, after reversing, the last element will be the first. But printing this will result in None.

iv. print(list_name[-1]) - This will print the last element in the list. If the list is sorted in descending order, the last element will be the smallest one.

So, none of the options will give the same output. However, if we consider the final state of the list after calling sort(), reverse(), and accessing the element at index -1, then sort() and reverse() would result in the same final state for the list (both would be in ascending order), but they don't return the same output.

This problem has been solved

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