Select the correct answerPredict the output and give your views for the given code snippet in C#include <stdio.h>void Function(int n, int j) {  if (j >= n)    return;  if (n-j > 0 && n-j >= j)    printf("%d %d ", j, n-j);  Function(n, j+1);} int main() {  int n = 10;  Function(n, 3);}Options3 7 5 6 5 53 7 4 6 5 53 7 4 6 6 53 7 4 6 5 6

The correct answer is 3 7 4 6 5 5.

Here's the step-by-step explanation:

1. The main function calls Function with n=10 and j=3.
2. In Function, it first checks if j is greater than or equal to n. If it is, it returns without doing anything. In this case, j is less than n, so it continues.
3. It then checks if n-j is greater than 0 and if n-j is greater than or equal to j. If both conditions are true, it prints j and n-j. In this case, n-j is 7 which is greater than 0 and also greater than j (3), so it prints "3 7 ".
4. It then calls Function again, this time with j+1 (which is 4).
5. The same process repeats. This time, n-j is 6 which is greater than 0 and also greater than j (4), so it prints "4 6 ".
6. It calls Function again, this time with j+1 (which is 5).
7. Again, n-j is 5 which is greater than 0 and equal to j, so it prints "5 5 ".
8. It calls Function again, this time with j+1 (which is 6). But this time, n-j is 4 which is less than j, so it doesn't print anything and just returns.
9. The same happens for all further recursive calls until j is equal to n, at which point it stops calling Function and just returns.

So, the final output is "3 7 4 6 5 5".