Consider the simultaneous choice of Jordan and Huy deciding what to bring to a dinner party. Both must choose to bring chips (C) or dip (D). If both choose chips (C) or both bring dip (D), the party is a disaster and the payoffs are 0 for everybody. If Huy brings dip (D) and Jordan brings chips (C) or vice versa, the party is a success and the payoffs are 10 for everybody. Which statement is true?Group of answer choicesThere is a unique Nash equillibriumThere are no Nash equillibriumThere are multiple Nash equilliriumThis is a prisoners’ dilemma
Question
Consider the simultaneous choice of Jordan and Huy deciding what to bring to a dinner party. Both must choose to bring chips (C) or dip (D). If both choose chips (C) or both bring dip (D), the party is a disaster and the payoffs are 0 for everybody. If Huy brings dip (D) and Jordan brings chips (C) or vice versa, the party is a success and the payoffs are 10 for everybody. Which statement is true?Group of answer choicesThere is a unique Nash equillibriumThere are no Nash equillibriumThere are multiple Nash equilliriumThis is a prisoners’ dilemma
Solution
There are multiple Nash equilibria.
Here's why:
A Nash equilibrium occurs when no player can improve their payoff by unilaterally changing their strategy, given the other player's strategy.
In this case, if Huy brings dip (D) and Jordan brings chips (C), neither player can improve their payoff by changing their strategy. So, (D,C) is a Nash equilibrium.
Similarly, if Huy brings chips (C) and Jordan brings dip (D), neither player can improve their payoff by changing their strategy. So, (C,D) is also a Nash equilibrium.
Therefore, the game has two Nash equilibria: (D,C) and (C,D).
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