A capacitor of capacitance 20 µF is charged to a potential difference of 500 V. The charge stored in the capacitor is:a) 1000 µCb) 10000 µCc) 0.1 Cd) 10 C
Question
A capacitor of capacitance 20 µF is charged to a potential difference of 500 V. The charge stored in the capacitor is:a) 1000 µCb) 10000 µCc) 0.1 Cd) 10 C
Solution
The charge (Q) stored in a capacitor can be calculated using the formula:
Q = CV
where: C is the capacitance, and V is the potential difference.
Given: C = 20 µF = 20 x 10^-6 F (since 1 µF = 10^-6 F) V = 500 V
Substituting these values into the formula, we get:
Q = (20 x 10^-6 F) x (500 V) = 10 x 10^-3 C = 10 mC
However, the options are given in µC, so we need to convert from mC to µC.
1 mC = 1000 µC
So, Q = 10 mC = 10 x 1000 µC = 10000 µC
Therefore, the correct answer is b) 10000 µC.
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