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The length of a rectangle is five times its width.If the perimeter of the rectangle is 96 m, find its area.

Question

The length of a rectangle is five times its width.If the perimeter of the rectangle is 96 m, find its area.

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Solution

Sure, let's solve this step by step.

Step 1: Let's denote the width of the rectangle as 'w'. According to the problem, the length of the rectangle is five times its width, so we can denote the length as '5w'.

Step 2: The formula for the perimeter of a rectangle is 2(length + width). We know from the problem that the perimeter is 96 m. So, we can set up the equation 2(5w + w) = 96.

Step 3: Simplify the equation. 2(6w) = 96, which simplifies to 12w = 96.

Step 4: Solve for 'w'. Divide both sides of the equation by 12 to get w = 8.

Step 5: Now that we have the width, we can find the length by multiplying the width by 5. So, the length is 5w = 5*8 = 40.

Step 6: Finally, we can find the area of the rectangle by multiplying the length by the width. So, the area is 40*8 = 320 square meters.

This problem has been solved

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