The kinetic energy of an object is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

1. If the speed was quartered, the kinetic energy would be:

KE = 1/2 * m * (v/4)^2
= 1/2 * m * v^2 / 16
= 143 J / 16
= 8.9375 J

2. If the mass was doubled and the speed was halved, the kinetic energy would be:

KE = 1/2 * 2m * (v/2)^2
= m * v^2 / 4
= 2 * 143 J / 4
= 71.5 J

Question

The kinetic energy of an object is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

1. If the speed was quartered, the kinetic energy would be:

KE = 1/2 * m * (v/4)^2
   = 1/2 * m * v^2 / 16
   = 143 J / 16
   = 8.9375 J

2. If the mass was doubled and the speed was halved, the kinetic energy would be:

KE = 1/2 * 2m * (v/2)^2
   = m * v^2 / 4
   = 2 * 143 J / 4
   = 71.5 J

Knowee AI · Accepted Answer

The kinetic energy of an object is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

1. If the speed was quartered, the kinetic energy would be:

KE = 1/2 * m * (v/4)^2
   = 1/2 * m * v^2 / 16
   = 143 J / 16
   = 8.9375 J

2. If the mass was doubled and the speed was halved, the kinetic energy would be:

KE = 1/2 * 2m * (v/2)^2
   = m * v^2 / 4
   = 2 * 143 J / 4
   = 71.5 J

The kinetic energy of an object is 143 J. What would the kinetic energy be if the speed was quartered? JoulesWhat if the mass was doubled and the speed was halved? Joules