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What will be the output of the following code snippet?1234567#include <stdio.h>int main() { int a = 5, b = 10; int result = a == b ? a + b : a - b; printf("%d", result); return 0;}

Question

What will be the output of the following code snippet?1234567#include <stdio.h>int main() { int a = 5, b = 10; int result = a == b ? a + b : a - b; printf("%d", result); return 0;}

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Solution

The output of the code will be -5.

Here's the step by step explanation:

  1. The code declares two integer variables, a and b, and assigns them the values 5 and 10 respectively.
  2. The next line is a ternary operation, which is a shorthand for an if-else statement. It checks if a is equal to b.
  3. If a is equal to b, it will execute a + b. If a is not equal to b, it will execute a - b.
  4. In this case, since a is not equal to b, it will execute a - b, which is 5 - 10, resulting in -5.
  5. The printf function then prints the result, which is -5.
  6. The program then returns 0, signaling successful execution of the program.

This problem has been solved

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