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Subtract the sum of 4t( t- 3m + 2s) and 2ts + 3tm from 5t(10s -3m +2t)

Question

Subtract the sum of 4t( t- 3m + 2s) and 2ts + 3tm from 5t(10s -3m +2t)

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20 – 3(2 + t) = 2t + 4

Simplify the following expression:(4t − 5t2) + 19(3t + 4)After simplifying, what number is multiplied by the t?

10t−22=−5(−2t+3)

Simplify. Express your answer using positive exponents.(3t3)(10t)

(8t − 7t2) + 11(5t + 2)

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