A 1.8 g potato core is submerged in sugar water. When it is removed, its mass is 1.6 g. What is the percentage loss of the potato's mass? Round your answer to the nearest hundredth of a percent.
Question
A 1.8 g potato core is submerged in sugar water. When it is removed, its mass is 1.6 g. What is the percentage loss of the potato's mass? Round your answer to the nearest hundredth of a percent.
Solution 1
To calculate the percentage loss of the potato's mass, follow these steps:
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First, determine the amount of mass lost. This is done by subtracting the final mass from the initial mass. In this case, 1.8 g (initial mass) - 1.6 g (final mass) = 0.2 g (mass lost).
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Next, calculate the percentage loss. This is done by dividing the mass lost by the initial mass and then multiplying by 100 to get a percentage. In this case, (0.2 g / 1.8 g) * 100 = 11.11%.
So, the potato lost approximately 11.11% of its mass.
Solution 2
To find the percentage loss of the potato's mass, we can use the formula:
Percentage loss = (Initial mass - Final mass) / Initial mass * 100
Given that the initial mass of the potato core is 1.8 g and the final mass is 1.6 g, we can substitute these values into the formula:
Percentage loss = (1.8 g - 1.6 g) / 1.8 g * 100
Simplifying this equation, we get:
Percentage loss = 0.2 g / 1.8 g * 100
Percentage loss = 0.1111 * 100
Percentage loss = 11.11%
Therefore, the percentage loss of the potato's mass is approximately 11.11%.
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